求y=sin(2x-π/6)的单调区间

题目

求y=sin(2x-π/6)的单调区间

答案

令2x-π/6=t,则y=f(t)=sint的单调区间是已知的,即：单调增区间：(-π/2+2kπ,π/2+2kπ)k∈Z单调减区间：(π/2+2kπ,3π/2+2kπ)k∈Z将t=2x-π/6带入后,解不等式即可：-π/2+2kπ＜2x-π/6＜π/2+2kπ即-π/6+kπ＜x...