复数运算题(√3+2i)z=6i

题目

复数运算题(√3+2i)z=6i
只记得题目,选项忘了.
(√3+2i)z=6i 求z是多少

答案

(√3+2i)z=6i
z=6i/(√3+2i)
=6i×(√3-2i)/[(√3+2i)(√3-2i)]
=(12-6√3i)/(3+4)
=(12-6√3i)/7