sin(2x+π/3)-根号3sin(2x+5π/6)怎么算?
题目
sin(2x+π/3)-根号3sin(2x+5π/6)怎么算?
答案
sin(2x+π/3)-√3sin(2x+5π/6﹚
=sin(2x+π/3)+√3sin﹙2x-π/6﹚
=sin(2x+π/3)-√3cos﹙2x+π/3﹚
=2[½sin(2x+π/3)-√3/2cos﹙2x+π/3﹚]
=2sin2x
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