3/2sin2x+3根号3/2cos2x

题目

3/2sin2x+3根号3/2cos2x
（3/2）sin2x+（3√3）/2cos2x 怎么化简

答案

(3/2)sin2x+(3√3/2)cos2x
=3*[(1/2)sin2x+(√3/2)cos2x]
=3*[sin2x*cos(π/3)+cos2x*sin(π/3)]
=3*sin[2x+(π/3)]