一道数学二次根式的题目.
题目
一道数学二次根式的题目.
已知a=根号三分之1 ,求 a平方-a分之根号下a平方-2a+1的值.
答案
a=根号三分之1=√3/3 a²=1/3
a平方-a分之根号下a平方-2a+1
=a²-√a²/a-2a+1
=a²-1-2a+1
=a²-2a
=1/3-2√3/3
=(1-2√3)/3
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