计算：log16(√128) lolg8(27) log9(16)

题目

计算：log16(√128) lolg8(27) log9(16)
请各位计算这三道题..
麻烦各位写出全过程..谢谢...

答案

log16(√128)
=log2^4[2^(7/2)]
=(7/2)/4
=7/8
log8(27)
=log2^3(3^3)
=log2(3)
log9(16)
=log3^2(2^4)
= (4/2)log3(2)
=2log3(2)