（1+根号2）X^2 - (1-根号2)X =0

题目

（1+根号2）X^2 - (1-根号2)X =0
9(2X-1)^2 - 4(2X+3)^2 =0
3X^2 +10X+4=0

答案

（1+√2）X^2 - (1-√2)X =0
X[（1+√2）X - (1-√2)] =0
X=0或X=(1-√2)/(1+√2）
X=0或X=(1-√2)^2/(1+√2)(1-√2)
X=0或X=-(1-√2)^2
X=0或X=2√2-3
9(2X-1)^2 - 4(2X+3)^2 =0
[3(2X-1) - 2(2X+3)][3(2X-1) + 2(2X+3)]=0
(6X-3-4X-6)(6X-3+4X+6)=0
(2X-9)(10X+3)=0
X=9/2或X=-3/10
3X^2 +10X+4=0
X^2 +10X/3+4/3=0
X^2 +10X/3+25/9-25/9+4/3=0
(X+5/3)^2-13/25=0
(X+5/3-√13/5)(X+5/3+13/5)=0
X=-5/3+√13/5/2或X=X=-5/3-√13/5/2