解三元一次方程 {3x+5y-6z=—18 {x/3=y/6=z/8
题目
解三元一次方程 {3x+5y-6z=—18 {x/3=y/6=z/8
答案
令x/3=y/6=z/8=t,则x=3t, y=6t, z=8t
∴3x+5y-6z=3*3t+5*6t-6*8t=-9t=-18
∴t=2
∴x=6, y=12, z=16
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