已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)

题目

已知Iab-2I+Ib=0-2I,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)

答案

我想您的题目是│ab-2│+│b-2│=0吧?∵│ab-2│≥0,│b-2│≥0∴ab=2,b=2∴a=1,b=2∴原式=1/(1×2)+1/(2×3)+..+1/(2007×2008)=1-1/2+1/2-1/3+..+1/2007-1/2008=1-1/2008=2007/2008明教为您解答,请点击[满意答案];...