已知(X+3)^2+|y+6|=02(3x-3y)-4(x-y)-2(x-y)

题目

已知(X+3)^2+|y+6|=02(3x-3y)-4(x-y)-2(x-y)

答案

解
(x+3)²+/y+6/=0
∴
x+3=0,y+6=0
∴x=-3,y=-6
∴x-y=-3+6=3
∴(3x-3y)-4(x-y)-2(x-y)
=3(x-y)-4(x-y)-2(x-y)
=(3-4-2)(x-y)
=-3(x-y)
=-3×3
=-9