解下列方程组 { x+y/2+x-y/3=1 4(x+y)-5(x-y)=-38

题目

解下列方程组 { x+y/2+x-y/3=1 4(x+y)-5(x-y)=-38
{ x+y/2+x-y/3=1
4(x+y)-5(x-y)=-38

答案

2x-y/6=1
4x+4y-5x+5y=-38
-x+9y=-38
-x=-38-9y
x=38+9y
2(38+9y)-y/6=1
76+18y-y/6=1
18y-y/6=-75
17又5/6y=-75
5/6y=-92
y=-110.4
x=955.6