将复数z=-2(sinπ/3-icosπ/3）化为三角形式,

题目

将复数z=-2(sinπ/3-icosπ/3）化为三角形式,

答案

z=-2(sinπ/3-icosπ/3）
=2(-sinπ/3+icosπ/3）
=2(-cos(π/6)+isin(π/6）)
=2(cos(π-π/6)+isin(π-π/6))
=2(cos(5π/6)+isin(5π/6))