if(++Time_Count = 50) return;中的return怎么理解?

题目

if(++Time_Count = 50) return;中的return怎么理解?
//
#include
#define uint unsigned int
#define uchar unsigned char
sbit RED_A = P0^0;
sbit YELLOW_A = P0^1;
sbit GREEN_A = P0^2;
sbit RED_B = P0^3;
sbit YELLOW_B = P0^4;
sbit GREEN_B = P0^5;
uchar Time_Count = 0,Flash_Count = 0,Operation_Type = 1;
void T0_INT() interrupt 1
{
x05TMOD = 0x01;
x05IE = 0x82;
x05TR0 = 1;
x05TH0 = (60000-50000)/256;
x05TL0 = (60000-50000)%256;
x05
x05switch(Operation_Type)
x05{
x05 x05case 1:
x05x05x05RED_A=0;YELLOW_A=0;GREEN_A=1;
x05x05x05RED_B=1;YELLOW_B=0;GREEN_B=0;
x05x05x05if(++Time_Count = 50) return;
x05x05x05Time_Count=0;
x05x05x05Operation_Type = 2;
x05x05x05break;
x05x05case 2:
x05x05x05if(++Time_Count = 8) return;
x05x05x05Time_Count=0;
x05x05x05YELLOW_A=!YELLOW_A;
x05x05x05GREEN_A=0;
x05x05x05if(++Flash_Count = 10) return;//黄灯闪烁5次
x05x05x05Flash_Count=0;
x05x05x

答案

if(++Time_Count != 50) return;
ruturn指的是返回以下这个循环体：
void T0_INT() interrupt 1
{
x05TMOD = 0x01;
x05IE = 0x82;
x05TR0 = 1;
x05TH0 = (60000-50000)/256;
x05TL0 = (60000-50000)%256;
x05
x05switch(Operation_Type)
x05{