已知3x2+4x-7=0,则6x4+11x3-7x2-3x-7=______.
题型:填空题难度:一般来源:不详
已知3x2+4x-7=0,则6x4+11x3-7x2-3x-7=______. |
答案
∵6x4+11x3-7x2-3x-7, =6x4+8x3-14x2+3x3+4x2-7x+3x2+4x-7, =2x2(3x2+4x-7)+x(3x2+4x-7)+(3x2+4x-7), =(3x2+4x-7)(2x2+x+1), 又3x2+4x-7=0, ∴原式=0. |
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