(1)∵①A+B-C=(2x2-3x2y-2xy2)+(x2-2xy2+y3)-(-x2+3x2y-y3) =2x2-3x2y-2xy2+x2-2xy2+y3+x2-3x2y+y3 =(2+1+1)x2+(-3-3)x2y+(-2-2)xy2+(1+1)y3 =4x2-6x2y-4xy2+2y3, ②A-B+C=(2x2-3x2y-2xy2)-(x2-2xy2+y3)+(-x2+3x2y-y3) =2x2-3x2y-2xy2-x2+2xy2-y3-x2+3x2y-y3 =(2-1-1)x2+(-3+3)x2y+(-2+2)xy2+(-1-1)y3 =-2y3, 所以,②A-B+C的运算结果的取值与x无关;
(2)选①,当x=-1,y=-时, 原式=4x2-6x2y-4xy2+2y3 =4×(-1)2-6×(-1)2×(-)-4×(-1)×(-)2+2×(-)3 =4+3+1- =7; 选②,当x=-1,y=-时,-2y3=-2×(-)3=. |