计算:(1)(22012-22011)0-(-12)-1-|-3|(2)(x+y-3)(x-y+3)
题型:解答题难度:一般来源:不详
计算: (1)(22012-22011)0-(-)-1-|-3| (2)(x+y-3)(x-y+3) |
答案
(1)原式=1-(-2)-3 =1+2-3 =0;
(2)原式=[x+(y-3)][x-(y-3)] =x2-(y-3)2 =x2-(y2-6y+9) =x2-y2+6y-9. |
举一反三
计算或化简 (1)(x2-xm)÷x2m (2)30-2-3+(-3)2-()-1 (3)(-a2)3+(-a3)2-a2-a3 (4)(x+1)(x-1)+x(2-x) (5)4(x+y)2-x(2y+x)-3(x2)2 (6)(y-x)2(x-y)+(x-y)3+2(x-y)2(y-x) |
计算: (1)(-3)0+(-)-2÷|-2| (2)(2x-3y)2-(3x+y)(3x-y) (3)(x+y)(x2+y2)(x-y) (4)(m-n-3)2 |
下列算式①(-)-3=-,②a2+2a-1=(a-1)2,③a8÷a8=a0(a≠0),④(a-b)3=a3-b3,⑤3x3(-2x2)=-6x5,其中正确的有______.(填写序号). |
最新试题
热门考点