计算:(a-2b+3c)(a+2b-3c).
题型:解答题难度:一般来源:不详
计算:(a-2b+3c)(a+2b-3c). |
答案
(a-2b+3c)(a+2b-3c) =[a-(2b-3c)][a+(2b-3c)] =a2-(2b-3c)2 =a2-(4b2-12bc+9c2) =a2-4b2+12bc-9c2. |
举一反三
计算下列各题 (1)(+1)(-1)+(-2)2(2)-. |
下列各式:a-b=b-a,(a-b)2=(b-a)2,x2+y2=(x+y)(x+y),-x2+y2=(-x+y)(-x-y),-a2+2ab-b2=-(a+b)2,a2b2+4ab-4=(ab-2)2,其中变形正确的有( )个. |
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