分解因式:(1)a2(a-1)+(1-a);(2)x2-2x-6y-9y2.
题型:解答题难度:一般来源:不详
分解因式:(1)a2(a-1)+(1-a);(2)x2-2x-6y-9y2. |
答案
(1)a2(a-1)+(1-a) =a2(a-1)-(a-1) =(a-1)(a2-1) =(a-1)(a-1)(a+1) =(a-1)2(a+1);
(2)x2-2x-6y-9y2 =x2-2x+1-1-6y-9y2 =(x-1) 2-(3y+1) 2 =[(x-1)-(3y+1)][(x-1)+(3y+1)] =(x-3y-2)(x+3y). |
举一反三
下列各式从左到右不是分解因式的是( )A.x2-1=(x-1)(x+1) | B.ax+ay=a(x+y) | C.x2-4x+4=(x-2)2 | D.x2y-xy2+1=xy(x-y)+1 |
|
分解因式: (1)-m2n+16mn-64n; (2)3(a-2b)2-27b2. |
将下列各式因式分 (1)100x2-81y2 (2)(x2+1)2-4x2 (3)(x-2)2+12(x-2)+36 (4)3x3-12x2y+12xy2. |
(1)已知:a+b=3,x-y=1,求a2+2ab+b2-x+y的值. (2)已知a-b=2005,ab=,求a2b-ab2的值. |
最新试题
热门考点