分解因式:x2-y2+3x-y+2=______.
题型:填空题难度:一般来源:不详
分解因式:x2-y2+3x-y+2=______. |
答案
x2-y2+3x-y+2 (x2-y2)+(x+y)+(2x-2y+2) =(x+y)(x-y)+(x+y)+2(x-y+1) =(x+y)(x-y+1)+2(x-y+1) =(x-y+1)(x+y+2); 故答案为(x+y+2)(x-y+1). |
举一反三
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