把下列各式分解因式:(1)x3y-xy3(2)(x2+4)-16x2(3)x(y-z)-y(z-y)
题型:解答题难度:一般来源:不详
把下列各式分解因式: (1)x3y-xy3 (2)(x2+4)-16x2 (3)x(y-z)-y(z-y) |
答案
(1)x3y-xy3, =xy(x2-y2), =xy(x+y)(x-y);
(2)(x2+4)-16x2, =(x2+4+4x)(x2+4-4x), =(x+2)2(x-2)2;
(3)x(y-z)-y(z-y), =x(y-z)+y(y-z), =(x+y)(y-z). |
举一反三
分解因式: (1)-x4+; (2)-8a2b+2a3+8ab2 |
下列各式由左边到右边的变形中,是分解因式的为( )A.x2-4x+4=x(x-4)+4 | B.a(x+y)=ax+ay | C.x2-16+3x=(x-4)(x+4)+3x | D.10x2-5x=5x(2x-1) |
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多项式x2-ax+因式分解为(x+)2,则a=______. |
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