填空:(1)x2+12x+______=(x+6)2;(2)x2-10x+______=(x-______)2;(3)x2+8x+______=(x+_____
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填空: (1)x2+12x+______=(x+6)2; (2)x2-10x+______=(x-______)2; (3)x2+8x+______=(x+______)2. |
答案
(1)x2+12x+36=(x+6)2; (2)x2-10x+25=(x-5)2; (3)x2+8x+16=(x+4)2. |
举一反三
配方:x2-4x+3=(x-□)2+△,请在“□、△”中填上适当的数,使等式成立______、______. |
若x2-2px+q=(x+)2-,则p=______,q=______. |
(1)x2-2x+______=(x-1)2;(2)x2+x+=(x+______)2. |
(1)x2+6x+9=(x+______)2, (2)x2-______+=(x-)2. |
配方:x2-3x+______=(x-______)2; 2y2+4y-3=2(y+______)2-5. |
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