解:⑴F=G=( M+m)g=(750+46)×103×10=7.96×106N⑵正常行驶用时:休息时间为:90min-53.57min=36.43min(3)f=0.05G=0.05×7.96×106N=3.98×105NF’=f W=F’S=3.98×105N×1500m=5.97×108J
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