2x(x-y)的4次方-x²（x-y)²+xy(y-x)² 因式分解

题目

2x(x-y)的4次方-x²（x-y)²+xy(y-x)² 因式分解
（a/2)-32a的4次方
（x²-5x）²+10（x²-5x）-96
求写上因式分解的过程...

答案

2x(x-y)的4次方-x²（x-y)²+xy(y-x)²
=x(x-y)²[2(x-y)²-x+y]
=x(x-y)²(2(x-y)²-(x-y)]
=x(x-y)³[2(x-y)-1]
=x(x-y)³(2x-2y-1)
（a/2)-32a的4次方
=a/2(1-64a³)
=a/2(1-4a)(1+4a+16a²)
（x²-5x）²+10（x²-5x）-96
=(x²-5x+16)(x²-5x-6)
=(x²-5x+16)(x+1)(x-6)