已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
题目
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y
答案
先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y [(x²+y²)-(x-y)²+2y(x-y)]/4y =[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y=[x²+y²-x²-y²+2xy+2xy-2y²]/...
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