已知0<β<π/4,π/4<α<3π/4,cos(π/4-α)=3/5,sin(3π/4-β)=5/13,求cos(α+β)的值
题目
已知0<β<π/4,π/4<α<3π/4,cos(π/4-α)=3/5,sin(3π/4-β)=5/13,求cos(α+β)的值
答案是-56/65【要过程】
答案
π/4<α<3π/4,-π/2<π/4-α<0cos(π/4-α)=3/5sin(π/4-α)=-4/50<β<π/4π/2<3π/4-β<3π/4sin(3π/4-β)=5/13cos(3π/4-β)=-12/13cos(α+β)=-cos[π-(α+β)]=-cos[(π/4-α)+(3π/4-β)]=-[cos[(π...
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