求救!计算要有过程:7又793分之560除1079分之1067除3又671分之228等于多少?

题目

求救!计算要有过程:7又793分之560除1079分之1067除3又671分之228等于多少?

答案

7又793分之560除1079分之1067除3又671分之228
(7+560/793) ÷ (1067/1079) ÷ (3+228/671)
= (7+560/793) ÷ (1067/1079) ÷ { (3×671+228) / 671 }
= (7+560/793) ÷ (1067/1079) ÷ (2241/671)
= (7+560/793) ÷ { (1067/1079) × (2241/671) }
= (7+560/793) ÷ { (1067 × 2241) / (1079 × 671) }
= (7+560/793) ÷ { (11×97 × 27×83) / (13×83 × 61×11) }
= (7+560/793) ÷ { (97×27) / (13×61) }
= (7+560/793) ÷ (97×27) / 793
= (7+560/793) × 793 / (97×27)
= 7 × (1+80/793) × 793 / (97×27)
= 7 × (793 + 80) × 1 / (97×27)
= 7 × 873 × 1 / (97×27)
= 7 × (97×9) × 1 / (97×27)
= 7