(1-3x)²+(2x-1)²＞13(x-1)(x+1)

题目

(1-3x)²+(2x-1)²＞13(x-1)(x+1)
3(x+2)²-3(x+1)(x-1)≤12x²-(6x-3)(2x+1)
²是平方
(x-2y+3z)²-(x+2y-3z)²
(3+1)(3²+1)(3的4次方+1)(3的8次方+1)(3的16次方+1)

答案

(1-3x)²+(2x-1)²＞13(x-1)(x+1)
1-6x+9x²+4x²-4x+1>13x²-13
10x