已知:XY的平方=-6,求-XY(X2次方Y的5次方+XY的3次方-2Y)的值
题目
已知:XY的平方=-6,求-XY(X2次方Y的5次方+XY的3次方-2Y)的值
答案
xy²=-6
原式=-xy[(xy²)²y+(xy²)y-2y]
=-xy[(-6)²y+(-6)y-2y]
=-xy(36y-6y-2y)
=-xy(28y)
=-28xy²
=-28×(-6)
=168
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