计算x的2方+3x+2分之x-1+2+x-x的2方分之6-4-x的2方分之10-x=

题目

计算x的2方+3x+2分之x-1+2+x-x的2方分之6-4-x的2方分之10-x=
（x的2方-x-6分之x的2方-4+x-3分之x+2)除以x-3分之x+1=
x-y分之x乘以x+y分之y的2方-x的4方-y的4方分之x的4方y除以x的2方+y的2方分之x的2方=

答案

(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)
=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)
=[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/(x+1)(x+2)(x-2)
=(x^2-3x+2-6x-12-x^2+9x+10)/(x+1)(x+2)(x-2)
=0/(x+1)(x+2)(x-2)
=0
（x的2方-x-6分之x的2方-4+x-3分之x+2)除以x-3分之x+1=
=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)]/[(x+1)/(x-3)]
=[(x-2)/(x-3)+(x+2)/(x-3)]*[(x-3)/(x+1)]
=[(x-2+x+2)/(x-3)][(x-3)/(x+1)]
=2x/(x+1)
x-y分之x乘以x+y分之y的2方-x的4方-y的4方分之x的4方y除以x的2方+y的2方分之x的2方
={[x/(x-y)]*y^2/(x+y)-x^4y/(x^4-y^4)}/(x^2+y^2)
=[xy^2/(x^2-y^2)-x^4y/(x^4-y^4)]/(x^2+y^2)
=(x^3y^2+xy^4-x^4y)/(x^4-y^4)(x^2+y^2)