1.已知M,N是正整数,且4m/(6m-3n)是整数.若m/n的最大值是a,最小值是b,则a+b= 已知实数1/p-1/q=1/(q+p)则q/p

题目

1.已知M,N是正整数,且4m/(6m-3n)是整数.若m/n的最大值是a,最小值是b,则a+b= 已知实数1/p-1/q=1/(q+p)则q/p

答案

1.设4m/(6m-3n)=R,将4m/(6m-3n)分子和分母同除以n,则4(m/n)/[6(m/n)-3]=R.得：m/n=3R/(6R-4)=3/(6-4/R),则：a=3/(6-4/1)=3/2,b=3/[6-4/(-1)]=3/10.则：a+b=3/2+3/10=9/5.2.1/p-1/q=1/(q+p),将等式两边同时乘以（p+q...