x²y²-x²y-xy²+x+y-1因式分解
题目
x²y²-x²y-xy²+x+y-1因式分解
答案
x²y²-x²y-xy²+x+y-1
=x²y(y-1)-x(y²-1)+(y-1)
=x²y(y-1)-x(y+1)(y-1)+(y-1)
=(y-1)(x²y-xy-x+1)
=(y-1)[xy(x-1)-(x-1)]
=(x-1)(y-1)(xy-1)
举一反三
已知函数f(x)=x,g(x)=alnx,a∈R.若曲线y=f(x)与曲线y=g(x)相交,且在交点处有相同的切线,求a的值和该切线方程.
我想写一篇关于奥巴马的演讲的文章,写哪一篇好呢?为什么好
最新试题
热门考点