(6(x+2)的平方-8(x+2)(x-2)+10(x+2))除以2(x+2)

题目

(6(x+2)的平方-8(x+2)(x-2)+10(x+2))除以2(x+2)
整式除法 一定要正确的,

答案

(6(x+2)的平方-8(x+2)(x-2)+10(x+2))除以2(x+2) ={2(x+2)[3(x+2)-4(x-2)+5]}/2(x+2) =[3(x+2)-4(x-2)+5] =3x+6-4x+8+5 =-x+19