(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1 (2^64+1)+1的个位数字是什么
题目
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1 (2^64+1)+1的个位数字是什么
答案
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1 (2^64+1)+1=(2-1)(2+1)(2^2+1).(2^32+1)+1=(2^2-1)(2^2+1).(2^32+1)+1=(2^4-1).(2^32+1)+1=.=(2^32-1)(2^32+1)+1=2^64-1+1=2^642^n的个位上是以:2、4、8、6循环64/4=...
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