y=ax+b+√cx+d的值域如何求

题目

y=ax+b+√cx+d的值域如何求
你看错题了吧

答案

y=[a/c*(cx+d)＋(b-ad/c)]/(cx+d)=a/c+(b-ad/c)/(cx+d)(b-ad/c)]/(cx+d)≠0y≠a/c值域{y|y≠a/c,y∈R}