实数x,y满足tanx=x,tany=y,且绝对值x不等于绝对值y,求sin(x-y)/(x-y)-sin(
题目
实数x,y满足tanx=x,tany=y,且绝对值x不等于绝对值y,求sin(x-y)/(x-y)-sin(
答案
sinx/cosx=tanx=x
sinx=xcosx
同理
siny=ycosy
所以原式=(sinxcosy-cosxsiny)/(x-y)-(sinxcosy+cosxsiny)/(x+y)
=(xcosxcosy-ycosxcosy)/(x-y)-(xcosxcosy+ycosxcosy)/(x+y)
=cosxcosy(x-y)/(x-y)-cosxcosy(x+y)/(x+y)
=cosxcosy-cosxcosy
=0
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