矩形abcd中.o为矩形外一点,角bod=90度,求证角aoc=90度
题目
矩形abcd中.o为矩形外一点,角bod=90度,求证角aoc=90度
答案
因为角bod=90度,所以0点在以bd为直径的圆周上,又因为在以bd为直径的圆周上ac也为其直径,所以o点在以ac为直径的圆周上,所以角aoc=90度
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