| 0 1 -1 | | 1 0 2 | x| 1 1 2 |=| 0 2 1 | | -1 -1 -1| 用矩阵方程求x

题目

| 0 1 -1 | | 1 0 2 | x| 1 1 2 |=| 0 2 1 | | -1 -1 -1| 用矩阵方程求x

答案

设a+1=x,b+2=y,c+3=z 1/a+1+1/b+2+1/c+3=0 ->1/x+1/y+1/z=0 ->yz+xz+xy=0 ,(a+1)^2+(b+2)^2+(c+2)^2=x^2+y^