求多项式8ab+{1-6ab-[-3b+2(ab-1)-5a-3b)]}的值,其中a5,b=3

题目

求多项式8ab+{1-6ab-[-3b+2(ab-1)-5a-3b)]}的值,其中a5,b=3

答案

8ab+{1-6ab-[-3b+2(ab-1)-5a-3b]}
=8ab+1-6ab-[-3b+2(ab-1)-5a-3b]
=2ab+1+3b-2(ab-1)+5a+3b
=2ab+1+6b-2ab+2+5a
=6b+5a+3
=6×3+5×5+3
=46