1.解不等式：2sin(2x-π/3）-1≥0

题目

1.解不等式：2sin(2x-π/3）-1≥0
2.解方程：2sin(2x-π/3）-1=0

答案

sin(2x-π/3）≥1/2
2kπ+π/6<=2x-π/3<=2kπ+5π/6
kπ+π/4<= x <=kπ+7π/12