(1)(-4)-(+13)+(-5)-(-9)(2)(-48)÷8-(-25)×(-6)(3)-24+(-3)2十5×(-6)(4)-14+(-1)5-(4÷2
题型:解答题难度:一般来源:山东省期中题
(1)(-4)-(+13)+(-5)-(-9) |
(2)(-48)÷8-(-25)×(-6) |
(3)-24+(-3)2十5×(-6) |
(4)-14+(-1)5-(4÷2)3-4÷23 |
答案
(1)(-4)-(+13)+(-5)-(-9) =(-4)+(-13)+(-5)+(+9) =[(-4)+(-13)+(-5)] +(+9) =(-22)+(+9)=-13 (2)(-48)÷8-(-25)×(-6) =(-6)-(+150) =(-6)+(-150) =-156 (3)-24+(-3)2+5×(-6) =-16+9+(-30) =-46+9 =-37 (4)-14+(-1)5-(4÷2)3-4÷23 =-1+(-1)-23-4÷8 =-2-8- = |
举一反三
(1)5× (-2)-90÷ (-15) | (2) |
(3)
| (4)-14-(1-0.5)÷ 3× [3-(-3)2] |
计算
(1)(-4)3×0.252= | (2)÷= | (3)m3·m·(m2)3 = | (4)(5-2x)( 2x+5) = | 计算×0.6÷×|-2.5|= | 有资料表明:某地区高度每增加100米,气温下降0.8℃。小明和小方想出一个测量山峰高度的方法,小明在山脚,小方在峰顶,他们同时在上午10点整测得山脚和山顶的气温分别为2.2℃和0.2℃,你知道山峰有多高吗? |
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