(1)(-1)2009+(-)-2-(π-1)0-|-3| =-1+4-1-3 =-1; (2)(22000-21999)0-(-)-2+(-0.125)9×810 =1-16-8a2 =-23; (3)(a-2b+1)(a+2b-1) =[a-(2b-1)](a+2b-1) =a2-(2b-1)2 =a2-4b2+4b-1; (4)(-3a2)2•a4-(-4a5)2÷(-a)2 =9a8-16a10× =-7a8 ∵a+1=0, ∴a=-1, ∴原式=-7a8=-7. 故答案为-1、-23、a2-4b2+4b-1、-7. |