计算:(1)(-2xy2)3+4xy2- 12x2y4;(2)(-1)-2+(12)-2-5÷(π-3)0;(3)用简便方法计算:20092-2010×2008
题型:解答题难度:一般来源:不详
计算:(1)(-2xy2)3+4xy2- x2y4; (2)(-1)-2+()-2-5÷(π-3)0; (3)用简便方法计算:20092-2010×2008; (4)[(x+y)(x-y)-(x-y)2+2y(x-y)]÷(4y). |
答案
(1)原式=-8x3y6+2x3y6=-6x3y6. (2)原式=1+4-5÷1=5-5=0. (3)原式=20092-(2009+1)=20092-20092+1=1. (4)原式=(x2-y2-x2+2xy-y2+2xy-2y2)÷(4y)=-y-x. |
举一反三
(1)计算:tan45°-cos30°+-(3.14-π)0 (2)解方程:2x2+3x-1=0. |
()0=______,(-)0×3-2=______. |
20050=______,(-)-2=______. |
计算题: (1)3+-2-3; (2)-(2+)2; (3)--()0. |
20050=______,(-3)-2=______. |
最新试题
热门考点