下列式子中,不成立的是( )A.(x-y+z)(x-y-z)=(x-y)2-z2B.(x+y-z)(x-y-z)=x2-(y-z)2C.(x-y-z)(x+y
题型:单选题难度:简单来源:不详
下列式子中,不成立的是( )A.(x-y+z)(x-y-z)=(x-y)2-z2 | B.(x+y-z)(x-y-z)=x2-(y-z)2 | C.(x-y-z)(x+y-z)=(x-z)2-y2 | D.(x-y-z)(x+y+z)=x2-(y+z)2 |
|
答案
A、(x-y+z)(x-y-z)=[(x-y)+z][(x-y)-z]=(x-y)2-z2,故正确; B、(x+y-z)(x-y-z)=[(x-z)+y][(x-z)-y]=(x-z)2-y2,故错误; C、(x-y-z)(x+y-z)=[(x-z)-y][(x-z)+y]=(x-z)2-y2,故正确; D、(x-y-z)(x+y+z)=[x-(y+z)][x+(y+z)]=x2-(y+z)2,故正确. 故选B. |
举一反三
已知(a+b+1)(a+b-1)=63,则a+b=______. |
计算(3a-b)(-3a-b)等于( )A.9a2-6ab-b2 | B.-9a2-6ab-b2 | C.b2-9a2 | D.9a2-b2 |
|
计算:(-3x-2)(-3x+2)=______. |
若x+y=1004,x-y=2,则代数式x2-y2的值是______. |
最新试题
热门考点