先观察下面的解题过程,然后解答问题:题目:化简(2+1)(22+1)(24+1).(2+1)(22+1)(24+1)=(2-1)(2+1)(22+1)(24+1
题型:解答题难度:一般来源:不详
先观察下面的解题过程,然后解答问题: 题目:化简(2+1)(22+1)(24+1). (2+1)(22+1)(24+1)=(2-1)(2+1)(22+1)(24+1)=(22-1)(22+1)(24+1)=(24-1)(24+1)=28-1. 问题:化简(3+1)(32+1)(34+1)(38+1)…(364+1). |
答案
原式=(3-1)(3+1)(32+1)(34+1)(38+1)(364+1),(4分) =(32-1)(32+1)(34+1)(38+1)(364+1), =(34-1)(34+1)(38+1)(364+1), =(38-1)(38+1)(364+1), =(364-1)(364+1),(8分) =(3128-1).(10分) |
举一反三
下列各式不能用平方差公式计算的是( )A.(a+2b)(a-2b) | B.(x+y)(y-x) | C.(-xy+1)(-xy-1) | D.(t-3)(3-t) |
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(3a-2b)(-3a-2b)=( )A.9a2-6ab-b2 | B.b2-6ab-9a2 | C.9a2-4b2 | D.4b2-9a2 |
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下列各式中,相等关系一定成立的是( )A.(x-y)2=(y-x)2 | B.(x+6)(x-6)=x2-6 | C.(x+y)2=x2+y2 | D.6(x-2)+x(2-x)=(x-2)(x-6) |
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下列多项式乘法中不能用平方差公式计算的是( )A.(a3+b3)(a3-b3) | B.(a2+b2)(b2-a2) | C.(2x2y+1)2x2y-1) | D.(x2-2y)(2x+y2) |
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