计算:(1)(6ab4)2÷(-2ab3)•(-frac{1}{2}abc2)    (2)(t+1)(t-5)-t2(3)(a2b3-a2b2)÷(ab)2(

计算:(1)(6ab4)2÷(-2ab3)•(-frac{1}{2}abc2)    (2)(t+1)(t-5)-t2(3)(a2b3-a2b2)÷(ab)2(

题型:解答题难度:一般来源:不详
计算:(1)(6ab42÷(-2ab3)•(-frac{1}{2}abc2)    
(2)(t+1)(t-5)-t2
(3)(a2b3-a2b2)÷(ab)2
(4)(5a-b22
(5)(a+2b-3)(a-2b+3)(6)(x+2)2(x-2)2
答案
(1)原式=36a2b8÷(-2ab3)•(-
1
2
abc2
=9a2b6c2

(2)原式=t2-5t+t-5-t2
=-4t-5;

(3)原式=(a2b3-a2b2)÷(a2b2
=b-1;

(4)原式=(5a)2-2•5a•b2+(b22
=25a2-10ab2+b4

(5)原式=[a+(2b-3)][a-(2b-3)]
=a2-(2b-3)2
=a2-4b2+12b-9;

(6)原式=[(x+2)(x-2)]2
=(x2-4)2
=x4-8x2+16.
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