计算(1)(x-y)(x+3)(2)(5a2+8a)+(3a2-7a+5)(3)(-3)5•(-3)2(4)x2y2(-x2y)(5)(2a+3b)(a-b)(

计算(1)(x-y)(x+3)(2)(5a2+8a)+(3a2-7a+5)(3)(-3)5•(-3)2(4)x2y2(-x2y)(5)(2a+3b)(a-b)(

题型:解答题难度:一般来源:不详
计算
(1)(x-y)(x+3)
(2)(5a2+8a)+(3a2-7a+5)
(3)(-3)5•(-3)2
(4)x2y2(-x2y)
(5)(2a+3b)(a-b)
(6)(5a3-2a+a2)÷(-2a)
答案
(1)(x-y)(x+3)=x2+3x-xy-3y;

(2)(5a2+8a)+(3a2-7a+5),
=5a2+8a+3a2-7a+5,
=8a2+a+5;

(3)(-3)5•(-3)2
=(-3)5+2
=-37

(4)x2y2(-x2y)=-x4y3

(5)(2a+3b)(a-b),
=2a2-2ab+3ab-3b2
=2a2+ab-3b2

(6)(5a3-2a+a2)÷(-2a)=-
5
2
a2-
1
2
a+1.
举一反三
计算
(1)(2x-y)(4x2-y2)(2x+y)
(2)-2(
1
3
x-
3
2
y)2
(3)(x-3y)(x-
1
2
y)
(4)(-
1
5
a3x4-
9
10
a2x3)÷(-
3
5
ax2
(5)x2-(x+2)(x-2)-(x+2)2
(6)(2x2+x)-[4x2-(3x2-x)]
题型:解答题难度:一般| 查看答案
已知n是正整数,x,n满足3nx+2n-32x=63,则x的最小值是______.
题型:填空题难度:一般| 查看答案
已知多项式M=x2+5x-a,N=-x+2,P=x3+3x2+5,且M-N+P的值与x的取值无关,求字母a的值.
题型:解答题难度:一般| 查看答案
求x2y-[4x2y-(xyz-x2z)-3x2z]-2xyz的值,其中负数x的绝对值是2,正数y的倒数等于它本身,负数z的平方等于9.
题型:解答题难度:一般| 查看答案
计算
(1)(-2x23÷(-x)2           
(2)(-2m-1)(3m-2)
题型:解答题难度:一般| 查看答案
最新试题
热门考点

超级试练试题库

© 2017-2019 超级试练试题库,All Rights Reserved.