把x2(x+1)-y(xy+x)分解因式为( )A.x(x-y)(x+y+1)B.x(x+y)(x-y+1)C.x(x-y)(x-y-1)D.x(x-y)(x
题型:单选题难度:简单来源:不详
把x2(x+1)-y(xy+x)分解因式为( )A.x(x-y)(x+y+1) | B.x(x+y)(x-y+1) | C.x(x-y)(x-y-1) | D.x(x-y)(x+y-1) |
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答案
x2(x+1)-y(xy+x) =x2(x+1)-xy(y+1) =x(x2+x-y2-y) =x[(x2-y2)+(x-y)] =x[(x+y)(x-y)+(x-y)] =x(x-y)(x+y+1). 故选A. |
举一反三
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