解:相似,A(28,0),B(0,28)∴OA=OB=28,∴∠BAO=45°过F作FM⊥PA于M,则AP=3t,FM=t当t=t1时,AP1=3t1,AF1=t1;当t=t2时,AP2=3t2 ,AF2=t2,所以又∵∠F1AP1=∠F2AP2=45°,∴△AF1P1∽△AF2P2。
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