设集合U={0,1,2,3,4,5},A={1,2},B={x∈Z|x2-5x+4<0},则∁U(A∪B)=( )A.{0,1,2,3}B.{5}C.{1,2
题型:单选题难度:一般来源:朝阳区二模
设集合U={0,1,2,3,4,5},A={1,2},B={x∈Z|x2-5x+4<0},则∁U(A∪B)=( )A.{0,1,2,3} | B.{5} | C.{1,2,4} | D.{0,4,5} |
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答案
集合B中的不等式x2-5x+4<0, 变形得:(x-1)(x-4)<0, 解得:1<x<4, ∴B={2,3}, ∵A={1,2}, ∴A∪B={1,2,3}, ∵集合U={0,1,2,3,4,5}, ∴∁∪(A∪B)={0,4,5}. 故选D. |
举一反三
集合M={-1,1,-2,2},集合N={1,4},则M∩N是( )A.{1,2} | B.∅ | C.{1} | D.{-1,1,-2,2,4} |
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设A={x|x2-3x-4=0},B={x|ax-1=0},且满足B⊆A,则满足条件的a组成的集合为( )A.{,-1} | B.{,0} | C.{-1} | D.{0,-1,} |
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设全集U={x|x<8,x∈N*},A⊆B={x|x=2n,n∈N*,n<3},则集合CUA的个数是( ) |
集合A={x题型:x-2|≤2},B={y|y=-x2,-1≤x≤2},则A∩B=( )A.{x|-4≤x≤4} | B.{x|x≠0} | C.{0} | D.∅ |
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难度:|
查看答案 命题“∀x∈R,x2+1≥1”的否定是( )A.∀x∈R,x2+1<1 | B.∃x∈R,x2+1≤1 | C.∃x∈R,x2+1<1 | D.∃x∈R,x2+1≥1 |
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