设全集U={1,2,3,4,5},集合M={1,2,3},N={2,3,5},则(CUM)∩(CUN)=( )A.ΦB.{2,3}C.{4}D.{1,5}
题型:单选题难度:一般来源:不详
设全集U={1,2,3,4,5},集合M={1,2,3},N={2,3,5},则(CUM)∩(CUN)=( ) |
答案
根据题意,M={1,2,3},则CUM={4,5}; N={2,3,5},则CUN={1,5}; 则(CUM)∪(CUN)={4} 故选C. |
举一反三
设U={1,2,3,4,5},若A∩B={2},(CU A)∩B={4},(CU A)∩(CU B)={1,5},则( )A.A={2} | B.A={2,3} | C.B={2,3} | D.B={2,3,4} |
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若集合M={1,2,3},N={2,3,4},则M∩N等于( )A.{2,3} | B.2,3 | C.{1,2,3,4} | D.{3} |
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设集合A={1,3},集合B={1,2,4,5},则集合A∪B=______. |
全集U={1,2,3,4,5},M={1,3,4},N={2,4,5},则CU(M∪N)=( ) |
设集合A={2,4,6,8,10},CUA={1,3,5,7,9},CUB={1,4,6,8,9},则集合A∩B=______. |
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